Answer:
I took the test, Its B) 41.1
5 : 3
D1 = 3km = 3000 m (1km = 1000m)
D2 = 1800m
Ratio of D1:D2
=3000/1800
=1000/600 (dividing by 3)
=10/6 (dividing by 100)
=5/3 (dividing by 2)
= 5 : 3
Answer:
T + V = 50
2T + (3/2) * V = 90
2T + 1.5V = 90
T = 50 * 1.5 - 90 * 1 / 1 * 1.5 - 2*1 = 30
V = 1 * 90 - 2 * 50 / 1 * 1.5 - 2 * 1 = 20
Step-by-step explanation:
T = 30
V = 20
Answer: C
The graph is continuous because there can be fractional values for time
Hello! Lets solve this :)
So for the first question :
h(t) = -16t^2 + 150
h(0)= -16 (0)^2 + 150
h(0)= -16(0) + 150
h(0)= 0 + 150
h(0)= 150 feet
Second question
We need to find here the time when the ball hit the ground; or when the height h(t) is 0.
In equation form
h(t) --> 0=16t^2 + 150
16t^2 = 150
t^2=150/16
t= <span>√150/16
t= 5</span><span>√6/4
t= 5 (2.45)/4
t= 3.06 seconds
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Hope this helps! If you have any other questions or would like further explanation just let me know! :)
