All categories

3 years ago

How is a sodium ion symbol written? so so- na na-

Chemistry

2 answers:

vfiekz [6]3 years ago

6 0

A sodium ion symbol is written as Na^+.

koban [17]3 years ago

5 0

Answer: Na⁺ or Na⁺¹

Explanation: Sodium as an element of the first group of the periodic system has atomic number 11. This means that there are 11 electrons negatively charged around the nucleus, and also 11 protons in the nucleus that are positively charged. As is known, the number of electrons and protons should be equal within the element to keep the element neutral. In order for the sodium element to become a sodium ion, one electron leaves its place and has 10 electrons, which is one less than the number of protons in the nucleus, so that the sodium ion is positive. The ion symbol is written by adding the superscript on the right as + or - in addition to the symbol of the element that is first written, depending on which ion is in question. In this case, + should be written as a superscript.

Also if the charge of the ion is say, +2 then it is written as a superscript behind the element symbol as +2. If it is +1 like with sodium ion, then only + can be written.

You might be interested in

When given any reaction how do I figure out the products and then balance it?

Tju [1.3M]

AB(aq)+C >A +CB(aq)
hope this helps

5 0

3 years ago

Which is heavier? A pound of cotton candy or a pound of marbles

Ugo [173]

Answer: both are equal

They weighed the same because they both a pound

6 0

2 years ago

Read 2 more answers

. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the

Anna [14]

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

$\frac{P}{T}=k$

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

$\frac{P1}{T1} =\frac{P2}{T2}$

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

P1= 0.450 atm
T1= 20 C= 293.15 K (being 0 C= 273.15 K)
P2=0.750 atm
T2= ?

Replacing:

$\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}$

Solving:

$T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }$

$T2=\frac{0.750 atm}{0.450 atm} *293.15K$

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

<u><em>The final temperature of sulfur dioxide gas is 215.43 C</em></u>

6 0

2 years ago

Which statement about stars is correct?

denis23 [38]

Answer:

A. star formation begins in a nebula.

Explanation:

4 0

2 years ago

Which type of bonding involves the complete transfer of a valence electron from a less electronegative atom to a more electroneg

Ivan

Answer:

Ionic or electrovalent bonds

Explanation:

Ionic or electrovalent bonds are interatomic or intramolecular bonds which are formed between two kinds of atoms having a large electronegativity difference usually 2.1.

Electronegativity is the property that combines the ability of an atom to gain or lose electrons. It is expressed as the tendency with which atoms of elements attracts valence electrons in a chemical bond.

In this bond type, a metal transfers its electrons to a more electronegative atom which is a non-metal.

6 0

2 years ago

Read 2 more answers