If they have one child, the probability that he or she will be affected is 1/4.
If they have two children, the probability that at least one of them will be affected is 7/16.
Explanation:
A cross between two heterozygous Aa individuals will produce the followinf offspring: 1/4 AA, 2/4 Aa and 1/4 aa.
Since the disease is recessive, 1/4 of the offspring will have the <em>aa </em>genotype and 3/4 of the offspring will be unaffected.
Every time they have children new gametes were generated <u>independently</u>.
The probability of having <u>no</u>affected children both times is, according to rules of probability for independent events, 3/4 × 3/4 = 9/16 (it's the probability of having a healthy child the first time multiplied by the probability of having a healthy child the second time).
The probability of having at least one affected child is 1 - probability of no affected children = 1 - 9/16 = 7/16.
The answer is true because this is essential when putting
them in formulas so that the worksheet may be able to provide the values or
find the values that are going to be calculated in the cell that has been
provided.
Density independent limiting factors affects all populations in an ecosystem, regardless of the population size. These include: Natural Disaster (Earthquakes)
Temperature (Extreme Temperatures, summer and winter = two totally opposite temperatures)