A as the lower temperature in Celsius corresponds to a lower Kelvin temperature thus reducing movement
Answer:
Tc^(+7) - 2.35*10^-5M
PO4(^-3) - 5.50*10^-5M
Explanation:
Tc3(PO4)7 <---> 
1 mol 3 mol 7 mol
7.85 X 10^-6 M 3*7.85*10^-6M 7*7.85*10^-6M
2.35*10^-5M 5.50*10^-5M
(i’m not very good at writing but use this as an idea)
changing the told would mess up the amount a daylight/nighttime because they’d be at a different angle from the sun
Answer:
7.35atm
Explanation:
Data obtained from the question include:
V1 = 28L
T1 = 42°C = 42 + 273 = 315K
P1 =?
V2 = 49L
T2 = 27°C = 27 + 273 = 300K
P2 = 4atm
Using P1V1/T1 = P2V2/T2, the original pressure can be obtained as follows:
P1V1/T1 = P2V2/T2
P1 x 28/315 = 4 x 49/300
Cross multiply to express in linear form
P1 x 28 x 300 = 315 x 4 x 49
Divide both side by 28 x 300
P1 = (315 x 4 x 49) /(28 x 300)
P1 = 7.35atm
Therefore, the original pressure is 7.35atm
Answer:
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