Answer:
x=6
Step-by-step explanation:
h(x) = -( x-2)^2 +16
We want when h(x) = 0
0 = -( x-2)^2 +16
Subtract 16 from each side
-16 = -( x-2)^2 +16-16
-16 = -( x-2)^2
Divide by -1
16= ( x-2)^2
Take the square root of each side
±sqrt(16) = sqrt(( x-2)^2 )
±4 = x-2
Add 2 to each sdie
2 ±4 = x-2+2
2+4 = x 2-4 =x
6 =x -2 =x
since time cannot be negative
x=6
Answer:
Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write
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Explanation:
The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.
So that's how I got
(x is between -4 and 5; inclusive of both endpoints)
Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"
Writing
is the set-builder notation way of expressing the domain. The
portion means "x is a real number"
(-2)(-24)
(-3)(-16)
(-4)(-12)
(-6)(-8)
-(-1)(-48)
1*48
2*24
3*16
4*12
6*8
Answer and Explanation:
The line seems to pass trough the points (0,6) and (-3,4).
Slope is:
The slope of the line should be .