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2 years ago

What a relationship between flame color and chemical name.

2 answers:

5 0

The flame gets the color which is determined by the properties of the atomic energy shells of the chemical element of the substance.

LekaFEV [45]2 years ago

3 0

Those transitions emit light of very specific frequencies, characteristic of the chemical element itself. Therefore, the flame gets the color, which is primarily determined by properties of the atomic energy shells of the chemical element of the substance being put into flame.

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Star A and Star B have measured stellar parallax of 1.0 arc second and 0.75 arc second, respectively. Which star is closer? How

zhuklara [117]

Answer:

Star A is closer than Star B

Explanation:

As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle

Here we can say

$angle = \frac{1 Parsec}{distance}$

so we have

$distance = \frac{1 Parsec}{angle}$

so here we have

angle subtended by Star A = 1 arc sec

angle subtended by star B = 0.75 arc sec

now we have

distance for star A is given as

$d_a = \frac{1 Parsec}{1} = 1 Parsec$

distance of star B is given as

$d_b = \frac{1 Parsec}{0.75} = 1.33 Parsec$

So star A is closer than star B

7 0

2 years ago

Which factors allow for life on Earth

Elan Coil [88]

Are there supposed to be multiple choices for this question?

6 0

2 years ago

Read 2 more answers

Una onda tiene una frecuencia de 350 Hz. ¿Cuál es su período?

Alika [10]

Answer:0.00285714285 seconds

Explanation:

period=1 ➗ frequency

Period=1 ➗ 350

Period=0.00285714285 seconds

7 0

2 years ago

A 40W lamp wastes 34 J of energy every second by heating its surroundings.

Artemon [7]

Answer:

$15\%$ .

Explanation:

The efficiency of a machine is the percentage of energy input that was turned into useful energy.

The power rating of this lamp is $40\; \rm W$ (same as $40\; \rm J \cdot s^{-1}$ ,) meaning that $40\; \rm J$ of energy is supplied to this lamp every second.

The question states that $34\; \rm J$ out of that $40\; \rm J$ of energy input would be turned into heat, which is not useful energy output in this scenario. Assuming that all other forms of energy loss is negligible. The rest of the $(40\; \rm J - 34\; \rm J) = 6\; \rm J$ of energy supplied to this lamp would be turned into useful energy output.

Thus, every second, this lamp would receive $40\; \rm J$ of energy input and would outputs $6\; \rm J$ of useful work. The efficiency of this lamp would be:

$\begin{aligned}& \text{Efficiency} \\ =\; & \frac{\text{Useful energy out}}{\text{Total energy in}} \times 100\% \\ =\; & \frac{6\; \rm J}{40\; \rm J} \times 100\%\\ =\; &15\% \end{aligned}$ .

4 0

1 year ago

Name of compounds a. H2Co3 b. NH4OH c.AlPO4 d.NaOH e.AuCI3

seraphim [82]

Answer:

a) Carbonic acid

b) ammonium hydroxide

c) Aluminum phosphate

d) Sodium hydroxide

e) Gold trichloride

Explanation:

I hope this will help you buddy 

3 0

2 years ago