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2 years ago

11

How to find median with even amount of numbers?

1 answer:

Paladinen [302]2 years ago

8 0

Sort the numbers in ascending or descending order, then eliminate the greatest and least numbers until you're left with the middle two. The median is the average of the last two numbers.

For example, the median for the set $\{2,10,-1,4\}=\{-1,2,4,10\}$ is 3 because the middle two numbers are 2 and 4, and their average is $\dfrac{2+4}2=3$ .

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A ________ exists between two variables when the values of one variable are somehow associated with the values of the other vari

motikmotik

Correlation would be the correct answer

8 0

2 years ago

An angle measures 114° less than the measure of its supplementary angle. What is the measure of each angle?

dezoksy [38]

Answer:

66°

Step-by-step explanation:

x+114°=180°

x+114°-114°=180°-114°

x=66°

3 0

2 years ago

Can any number be written in scientific notation

choli [55]

Yes, I'm relatively sure any number can be written in scientific notation.

5 0

2 years ago

Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A

Vlad [161]

Answer:

$y(x)=sin(2x)+2cos(2x)$

Step-by-step explanation:

$y''+4y=0$

This is a homogeneous linear equation. So, assume a solution will be proportional to:

$e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda$

Now, substitute $y(x)=e^{\lambda x}$ into the differential equation:

$\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0$

Using the characteristic equation:

$\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0$

Factor out $e^{\lambda x}$

$e^{\lambda x}(\lambda ^2 +4) =0$

Where:

$e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda$

Therefore the zeros must come from the polynomial:

$\lambda^2+4 =0$

Solving for $\lambda$ :

$\lambda =\pm2i$

These roots give the next solutions:

$y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}$

Where $c_1$ and $c_2$ are arbitrary constants. Now, the general solution is the sum of the previous solutions:

$y(x)=c_1 e^{2ix} +c_2 e^{-2ix}$

Using Euler's identity:

$e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)$

$y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\$

Redefine:

$i(c_1-c_2)=c_1\\\\c_1+c_2=c_2$

Since these are arbitrary constants

$y(x)=c_1sin(2x)+c_2cos(2x)$

Now, let's find its derivative in order to find $c_1$ and $c_2$

$y'(x)=2c_1 cos(2x)-2c_2sin(2x)$

Evaluating $y(0)=2$ :

$y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2$

Evaluating $y'(0)=2$ :

$y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1$

Finally, the solution is given by:

$y(x)=sin(2x)+2cos(2x)$

5 0

2 years ago

Find the total lateral area of the following

maxonik [38]

Answer:

15π cm²

Step-by-step explanation:

The total lateral area of a cone

= πr√h² + r²

= √h² + r² = l

h = Height = 4cm

r = radius = 3cm

Hence:

= π × 3 √4² + 3²

= 3π × √16 + 9

= 3π × √25

= 3π × 5

= 15π cm²

7 0

2 years ago