Answer:
Step-by-step explanation:
The question is not correct (particularly the expression for the area)
A=2lh+2wh
Now we are expected to solve for l, that is we are going to make l subject of the formula, we have
let us take the second term on the RHS to the LHS
we can now divide both sides by 2h we have
hence the expression for the length is
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
Answer:
y = - 
x - 3
Step-by-step explanation:
The equation of a line in slope- intercept fprm is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x + 7 is in slope- intercept form
with slope m = 3
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - , thus
y = - x + c ← is the partial equation of the perpendicular line
To find c substitute (3, - 4) into the partial equation
- 4 = - 1 + c ⇒ c = - 4 + 1 = - 3
y = - x - 3 ← equation of perpendicular line
