We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:
Where represents the number of objects/people in the set and represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set
Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get
Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
no
Step-by-step explanation:
I goo.g.led, sorry me dum lol
Answer:
............................
Step-by-step explanation:
There's no picture for me to help you with
Answer:
144.44
Step-by-step explanation:
C = 2 x π x r . C = 2 x 3.14 x 23 = 144.44