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3 years ago

Given that QRSTU=QXWVU, find

Mathematics

2 answers:

Mrac [35]3 years ago

7 0

Angle UQR = Angle UQX since they are corresponding angles. Note how the top polygon reflects over the line QU to get the bottom polygon.

So because of this, and because angle UQX = 45, this means the answer is 45 degrees

Travka [436]3 years ago

4 0

Answer:

$m\angle UQR=45^{\circ}$

Step-by-step explanation:

We have been given that pentagon QRSTU is equal to pentagon QXWUV. We are asked to find the measure of angle UQR.

Upon looking at our given image, we can see that both pentagons share a common side that is QU.

We can also see that both pentagons are symmetric about line QU.

Since measure of angle UQX is 45 degree, therefore, the measure of angle UQR will be 45 degrees as well.

You might be interested in

Differentiate x^2 e^x logx

zimovet [89]

Product rule:

$\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)$

$=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}$

Power rule:

$\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x$

The exponential function is its own derivative:

$\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x$

Assuming the base of $\log x$ is $e$ , its derivative is

$\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x$

But if you mean a logarithm of arbitrary base $b$ , we have

$y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}$

$\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}$

So we end up with

$2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x$

$=xe^x(2\log x+x\log x+1)$

8 0

2 years ago

█ HURRY IF YOUR SMART ANSWER THIS AND ILL GIVE YOU FREE POINTS █

erastova [34]

Answer:

C i think

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Solve the equation<br> 15x+2=45x+4

BaLLatris [955]

15x + 2 = 45x + 4

Subtract 2 from both sides, as well as subtracting 45x from both sides.

15x - 45x = 4 - 2

-30x = 2

Divide both sides by -30.

x = 2/-30

x = - 1/15

~Hope I helped!~

5 0

2 years ago

............................

prohojiy [21]

Ahh yes, negative exponents always give us a scare once and a while. All the negative means is to flip the position of its base. For instance, if x has a negative exponent and x in the denominator, all you would have to do is move x to the numerator with the same power (except it's no longer negative). Before we substitute x and all the other variables which the values given, let's eliminate the negatives first.

After flipping positions/eliminating the negative exponents it should look like this:

$\frac{ 2^{2} x^{3} }{ y^{5} }$
which simplifies to
$\frac{ 4 x^{3} }{ y^{5} }$
now that everything is simplified, and all negative exponents are eliminated we can substitute x with 2, and y with (-4).
$\frac{4 (2)^{3} }{ (-4)^{5} }$
which simplifies to
$\frac{4(8)}{(-1024)} = \frac{32}{-1024} = - \frac{1}{32}$

Final Answer: - \frac{1}{32} [/tex]

4 0

2 years ago

How do I find the answer to 10=7-m

andrey2020 [161]

Answer:

M=-3

Step-by-step explanation:

10=7-m

Subtract 7 from both sides

3=-m

Divide by negative

-3=m

3 0

2 years ago