Triangle,quadrilateral,pentagon,hexagon,octagon,decagon.
Triangle quadrilateral octagon - regular
rest are not. Someone might need to check me if im right about regular and irregular :) Hope I helped
It is given that, B ≅ BC and AD ≅ CD
We need BD perpendicular to AC, then only we can say triangles AXB and CXB are congruent using the HL theorem.
If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.
from the given information ABCD is a square
If BD and AC bisect each other then AX = CX
Then only we can immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem
So right now you see that you have x and y intercept right? Then plug those intercepts in equation that you have and solve for z. Which means z=5(1)(1) will be 5, 5(4)(1) will be 20, and 5(1)(2) will be 10. So, overall you have 5, 20, 10.
Cgagcadhfhfjooguo! duolujto