The statement best describes the difference between a substance with a pH of 3.0 and a substance with a pH of 6.0 is - The substance with the lower pH has 1,000 times as many hydrogen ions per volume of water.
pH is the scale or measure for the substance about its acidic or basic strength. It ranges from 0 to 6.9 which is acidic and 7.1 to 14 which is basic.
Acidic substance has high concentration of Hydrogen ions whereas, basic substance has low concentration of hydrogen ions, however for the OH⁻ ions it is reverse.
- Concentration of hydrogen ions is inversely related to its pH
- More hydrogen ions present, the lower the pH
- The fewer hydrogen ions, the higher the pH
We know,
pH = -log() then,
=> 3 = -log ()
=> = (for pH = 3)
=> pH = -log()
=> 6 = -log ()
=> = (for pH = 6)
Thus, The substance with the lower pH (3) has 1000 times as many hydrogen ions per volume of water.
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Panel surface area =34m×46m=1,564m^2
total power =1564m^2×1390w/m^2
=2173960watts
now you must calculate total energy.
Energy = power×Time
However time must be in seconds so we multiply 2hrs×60min×60s=7200seconds
7200s×2173960w =15,652,512,000 joules of energy
Answer:
Sound waves transfer energy by causing successive compressions and rarefactions in the particles of the medium without transporting the medium particles themselves. Sound in solids can also manifest as transverse waves, causing crests and troughs in the propagation medium.
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The magnitude of the magnetic moment due to the electron's motion is .
<h3>
What is magnetic moment?</h3>
The magnetic pull and direction of a magnet or other object that produces a magnetic field are referred to as the magnetic moment in electromagnetism. Things that have magnetic moments include electromagnets, permanent magnets, various compounds, elementary particles like electrons, and a number of celestial objects (such as many planets, some moons, stars, etc).
The term "magnetic moment" really refers to the magnetic dipole moment of a system, which is the portion of the magnetic moment that can be represented by an equivalent magnetic dipole or a pair of magnetic north and south poles that are only very slightly apart. The magnetic dipole component is adequate for sufficiently small magnets or over sufficiently large distances.
Calculations:
radius=
velocity=
Working formula, M=N/A
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M=
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