When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12
So in order that the given equation has double roots, the possible values of b are ± 12.
That's the beginning of Euler's number ' e '.
It falls between the square roots of 7 and 8 .
Hey ! You know what !
It falls between the square roots of any integer
less than 8 and any integer greater than 7 .
Answer:
20ft
Step-by-step explanation:
Answer:their is no photo
Step-by-step explanation: