Answer:
Explanation:
Given,
Distance travelled ( d ) = 176.4 meters
Time taken ( t ) = 4.5 seconds
<u>Finding </u><u>the </u><u>speed </u><u>of </u><u>a </u><u>cheetah</u>
Speed
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<u>Let's </u><u>learn </u><u>about </u><u>Speed </u> :
Suppose a body moves 20 m in 2 seconds, either on a curved path or on a straight path. So , 10 m is the distance travelled by the body in each second which can be written as 10 m/s. This is called speed of the body. Thus, <u>Speed </u><u>is </u><u>defined </u><u>as </u><u>the </u><u>distance</u><u> </u><u>travelled</u><u> </u><u>per </u><u>unit </u><u>time.</u> It is the rate of distance travelled by a body.
Mathematically,
In SI system, the unit of distance is metre and time is second. Thus , the <u>SI </u><u>unit </u><u>is </u><u>speed </u><u>is </u><u>m/</u><u>s.</u>
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According to the periodic table, all the elements, except hydrogen, are considered alkaline metals. ie. Li, Na, K, Rb, Cs, Fr.
Answer:
there are 2188 people at the game
Explanation:
Given the data in the question;
we know that decibel is defined as; dB = 10log(l/l₀)
so if one produces an intensity l₁, it results in 69.6 dB
69.6 = 10log(l₁/l₀) ---- equ1
also. if x number of people produces this intensity, it result to 103 dB
103 = 10log(xl₁/l₀)
103 = 10( log(l₁/l₀) + log(x) )
103 = 10log(l₁/l₀) + 10log(x) ----- equ2
input equation 1 into to equation 2
103 = 69.6 + 10log(x)
10log(x) = 103 - 69.6
10log(x) = 33.4
divide both side by 10
log(x) = 3.34
x =
x = 2187.76 ≈ 2188
Therefore, there are 2188 people at the game
Answer: The different speed of sound waves in water and in air
Explanation:
In general, sound (which is a mechanical wave) travels faster in solids than in liquids or gases. This is because the speed of mechanical waves is determined by a relationship between the elastic properties of the medium in which they are propagated and the mass per unit volume of the medium (that is: density).
In other words: The speed of sound varies depending on the medium through which the sound waves travel.
This is why Jason notices that sounds underwater (a liquid medium) are different from sounds above water (a gas medium: air).