Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).
Let <em>x</em> be the inverse. Then <em>x</em> is such that
23<em>x</em> ≡ 1 (mod 1000)
Use the Euclidean algorithm to solve for <em>x</em> :
1000 = 43×23 + 11
23 = 2×11 + 1
→ 1 ≡ 23 - 2×11 (mod 1000)
→ 1 ≡ 23 - 2×(1000 - 43×23) (mod 1000)
→ 1 ≡ 23 - 2×1000 + 86×23 (mod 1000)
→ 1 ≡ 87×23 - 2×1000 ≡ 87×23 (mod 1000)
→ 23⁻¹ ≡ 87 (mod 1000)
Step 2 because the answer is 1 is simplified
Answer:
<h2>12 computers = 24 students</h2>
Step-by-step explanation:
<h2>3 computers = 6 students</h2><h2>X computers = 24 students</h2><h2>cross multiply</h2><h2>6x = 3 × 24</h2><h2>6x = 72</h2><h2>divide both sides by 6</h2><h2>X = 12</h2>
Answer:
530.66 cm²
Step-by-step explanation:
take half the diameter of 26 and that gives you the radius of 13
A =π· r²
A = 3.14 x 169
Answer: 2n + 2 should be your answer
