Using phenol, dimethyl sulfate, and naoh, show how you would synthesize methyl phenyl ether.
1 answer:
The synthesis of Methyl Phenyl Ether is shown below,
The synthesis takes place in two steps,
Step 1: Formation of Sodium Phenoxide:
Phenol being more acidic than Alcohols with pKa ≈ 10 can loose its proton attached to oxygen atom, as the resulting phenoxide ion is stabilized by resonance. Therefore, when phenol is treated with NaOH (bBase) it looses proton and forms Sodium Phenoxide.
Step 2: Formation of Methyl Phenyl Ether:
The Phenoxide ion formed in first step when treated with Dimethyl Sulfate produces Methyl Phenyl Ether through a Williamson's Ether synthesis Reaction. Dimethyl sulfate is a well known alkylating agent when treated with phenols, thiols and amines. Dimethyl sulfate readily transfers the methyl group and forms NaSO₄CH₃.
The reaction is as follow,
The synthesis takes place in two steps,
Step 1: Formation of Sodium Phenoxide:
Phenol being more acidic than Alcohols with pKa ≈ 10 can loose its proton attached to oxygen atom, as the resulting phenoxide ion is stabilized by resonance. Therefore, when phenol is treated with NaOH (bBase) it looses proton and forms Sodium Phenoxide.
Step 2: Formation of Methyl Phenyl Ether:
The Phenoxide ion formed in first step when treated with Dimethyl Sulfate produces Methyl Phenyl Ether through a Williamson's Ether synthesis Reaction. Dimethyl sulfate is a well known alkylating agent when treated with phenols, thiols and amines. Dimethyl sulfate readily transfers the methyl group and forms NaSO₄CH₃.
The reaction is as follow,
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The concentration equilibrium constant is
Explanation:
The chemical equation for this decomposition of ammonia is
↔
The initial concentration of ammonia is mathematically represented a
The initial concentration of nitrogen gas is mathematically represented a
So looking at the equation
Initially (Before reaction)
During reaction(this is gotten from the reaction equation )
(this implies that it losses two moles of concentration )
(this implies that it gains 1 moles)
(this implies that it gains 3 moles)
Note : x denotes concentration
At equilibrium
Now since
Now the equilibrium constant is
substituting values
