when 22 grams of water undergoes a temeprature change from 35 ˚C to 65 ˚C, how much energy does the water absorb? The specific h
eat of water is 4.184.
1 answer:
Answer: 2761.44 joules
Explanation:
The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = ?
Mass of oil = 22g
C = 4.184Jg°C
Φ = (Final temperature - Initial temperature)
= 65°C - 35°C = 30°C
Then, Q = MCΦ
Q = 22g x 4.184Jg°C x 30°C
Q = 2761.41 Joules
Thus, water absorb 2761.44 joules of heat.
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