Answer:
My favorate activies is skateboareding, and I prerfer outdoor actives.
Explanation:
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Τ = Iα (torque equation)
Moment of inertia of disc about axis perpendicular to the plane of disc and passing through its centre = MR²/2
∴ 12 = MR²/2 × 5.7
∴ 12 = M(0.5)²/2 × 5.7
∴ M = 12 × 2 /5.7 × 0.5² = 16.84 Kg
Answer:
(a) x = 0.25 m
(b) v = 1.46 m/s
(c) v = 2.4 m/s
Explanation:
mass (m) = 10.3 kg
force from thrust (F) = 240 N
spring constant (k) = 400 N/m
stretch distance from thrust (y) = 30 cm = 0.3 m
acceleration due to gravity (g) = 9.8 m/s^{2}
(A) from mg = kx
compression (x) = mg/ k
x =
x = 0.25 m
(B) from the conservation of forces
(Fy) + (0.5k) = (0.5k) + mgh + (0.5m)
v = ) - (0.5k) - mgh }{0.5m}[/tex]}[/tex]
v = ) - (0.5 x 400 x ) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]
v = 1.46 m/s
(C) if the rocket weren't attached to the spring, the conservation of energy equation becomes
(Fy) + (0.5k) = mgh + (0.5m)
v = ) - mgh }{0.5m}[/tex]}[/tex]
v = ) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]
v = 2.4 m/s