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2 years ago

15

2.3 is 46% of what number

2 answers:

zaharov [31]2 years ago

6 0

Answer:

1.06
I apologized if this is incorrect.

Liono4ka [1.6K]2 years ago

3 0

Answer:

46% × 2.3 =

(46 ÷ 100) × 2.3 =

(46 × 2.3) ÷ 100 =

105.8 ÷ 100 =

1.058 ≈

1.06;

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Timothy stated that the sum of 0.9 + (-9/10) was 18/20.

Evgesh-ka [11]

Answer:

18/10

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

I need help with both of these questions please

tankabanditka [31]

Answer:

$\frac{22}{30} = \frac{11}{15}$

and

$\frac{176}{7} = 25 \frac{1}{7}$

Step-by-step explanation:

First make all the fractions into improper fractions

$1\frac{5}{6} = \frac{11}{6} \\\\2\frac{1}{2} = \frac{5}{2} \\\\3\frac{1}{7} = \frac{22}{7}$

After doing that put them back into the problems

Problem 1)

$1\frac{5}{6}$ ÷ $2\frac{1}{2}$ , plug in the improper fractions

$\frac{11}{6}$ ÷ $\frac{5}{2}$

to divide, you need to flip the second fraction and multiply

$\frac{11}{6}$ · $\frac{2}{5}$ = $\frac{22}{30}$

then reduce

$\frac{22}{30} = \frac{11}{15}$

Problem 2)

$3\frac{1}{7}$ ÷ $\frac{1}{8}\\$

Plug in improper fraction

$\frac{22}{7}$ ÷ $\frac{1}{8}\\$

Then flip second fraction and multiply

$\frac{22}{7}$ · $\frac{8}{1}$

Multiply

$\frac{176}{7}$

Reduce, or make it a mixed number

$\frac{176}{7} = 25 \frac{1}{7}$

3 0

2 years ago

Out of a total of 50 high school students, 14 plan to go to the basketball playoff game Friday night if there are 1450 students

Viefleur [7K]

Answer:

1131 students, is the best prediction.

Step-by-step explanation:

1450 divided by 50 = 29

50 - 14 = 36

36 x 29 = 1131

6 0

1 year ago

Please I need help with this!!!!!!!

inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

$x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}$

$x=\sqrt[3]{5^4}$ [Since, $a^{\frac{1}{3}}=\sqrt[3]{a}$ ]

$x=\sqrt[3]{5\times 5\times 5\times 5}$

Step 5:

$x=\sqrt[3]{(5)^3\times 5}$

$x=\sqrt[3]{5^3}\times \sqrt[3]{5}$

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

$(3x-1)^{\frac{1}{5}}=2$

Step 1:

$(3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}$

Step 2:

$(3x-1)=2^5$

Step 3:

$3x=32+1$

Step 4:

$x=11$

4). By substituting $x=11$ in the original equation.

$(3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}$

$=(2^5)^\frac{1}{5}$

$=2$

There is no extraneous solution.

3 0

1 year ago

In triangle ABC, a = 9, c = 5, and B = 120°. Find b2.

anygoal [31]

Answer:

(D) $b^2=151$

Step-by-step explanation:

Given: In triangle ABC, a=9, c=5 and ∠B=120°.

To find: The value of $b^2$ .

solution: It is given that In triangle ABC, a=9, c=5 and ∠B=120°.

Now, using the law of cosines, we get

$b^2=a^2+c^2-2(a)(c)cosB$

Substituting the given values, we get

$b^2=9^2+5^2-2(9)(5)cosB$

$b^2=81+25-90(\frac{-1}{2})$

$b^2=81+25+45$

$b^2=151$

which is the required value of $b^2$ .

Therefore, option D is correct.

3 0

2 years ago