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2 years ago

5

Greg was adding two numbers on a number line. He started at +4 and then he added -6. He wrote that his number was -2. Is Gregs a

nswer reasonable?

2 answers:

Klio2033 [76]2 years ago

5 0

Yes. Greg's answer is reasonable.

Softa [21]2 years ago

4 0

Yes it is reasonable hope this helps! :)

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Find the value of X for the given parallelogram

KatRina [158]

Opposite angles in a parallelogram are congruent

So,

6x-10 = 2x + 50

Now solve like a normal equation

4x = 60
x = 15

8 0

1 year ago

Zack deposited $1,200 in a savings account that paid 7.75% simple

Eddi Din [679]

<span>The correct answer is: Option (C) $1393.21

Explanation:
At the beginning of the Second year, the total balance would be:

$1200 + ($1200 * 7.75 / 100) = $1293

At the beginning of the Third year, the total balance would be:
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3 years ago

Read 2 more answers

Please help i would really appreciate it.

vredina [299]

(1,4) this is because the flip over y axis does not touch the y value but gives the opposite of the x value

8 0

2 years ago

Read 2 more answers

If y-18=14 what is the value of 3(y+5)?

svlad2 [7]

$y-18=14\ \ \ /+18\\\\y-18+18=14+18\\\\y=32\\\\substitute\ to\ 3(y+5):\\\\3\cdot(32+5)=3\cdot37=111$

4 0

2 years ago

The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?

AleksAgata [21]

Answer:

$\large \boxed{2}$

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

$\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}$

Check:

$\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}$

It checks.

7 0

2 years ago