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2 years ago

Find the percent of markup round to the nearest tenth

1 answer:

3 0

The first step in solving this problem is to compute the amount of markup. You can do this by deducting the original price to the marked up price.

$70.00 - $35.50 = $34.50

To get the percent of markup, you have to divide the amount of markup to the original price.

$34.50 / $35.50 = 97.2%

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Who knows this work?

Diano4ka-milaya [45]

Number 13 would be 4/12 because four ounces are vanilla

8 0

2 years ago

Read 2 more answers

Let C = C1 + C2 where C1 is the quarter circle x^2+y^2=4, z=0,from (0,2,0) to (2,0,0), and where C2 is the line segment from (2,

trapecia [35]

Not much can be done without knowing what $\mathbf F(x,y,z)$ is, but at the least we can set up the integral.

First parameterize the pieces of the contour:

$C_1:\mathbf r_1(t_1)=(2\sin t_1,2\cos t_1,0)$
$C_2:\mathbf r_2(t_2)=(1-t_2)(2,0,0)+t_2(3,3,3)=(2+t_2, 3t_2, 3t_2)$

where $0\le t_1\le\dfrac\pi2$ and $0\le t_2\le1$ . You have

$\mathrm d\mathbf r_1=(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
$\mathrm d\mathbf r_2=(1,3,3)\,\mathrm dt_2$

and so the work is given by the integral

$\displaystyle\int_C\mathbf F(x,y,z)\cdot\mathrm d\mathbf r$
$=\displaystyle\int_0^{\pi/2}\mathbf F(2\sin t_1,2\cos t_1,0)\cdot(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
${}\displaystyle\,\,\,\,\,\,\,\,+\int_0^1\mathbf F(2+t_2,3t_2,3t_2)\cdot(1,3,3)\,\mathrm dt_2$

5 0

2 years ago

I NEED HELP ASAP PLS PLS

masha68 [24]

Answer:

Mia: 90 and Isabella: 30

Step-by-step explanation:

Mia: 60 x 0.5 (50%) is 30

Isabella: 60 x 1.5 (150%) is 90

6 0

2 years ago

Aurora is planning to participate in an event at her school's field day that requires her to complete tasks at various stations

labwork [276]

Step-by-step explanation:

A. this is a geometric sequence.

according to y-coordinates =>

3, 6, 12, 24

have a T1 = 3 and ratio = 6/3 = 2

B. the formula = Tn = r. T(n-1)

T5 = 2. T4

= 2. 24 = 48 minutes

C. the formula : Tn = T1 . r^(n-1)

T9 = 3. 2^(9-1)

= 3. 2^8

= 3. 256

= 768 munutes

6 0

2 years ago

According to the graph, how far did the object move between the second and third seconds?

Setler79 [48]

Answer:

Your answer would be B

Step-by-step explanation:

This is because in between the 2nd and 3rd seconds, there is a 2 unit space so that is how far the object moved in between these seconds,

Hope this helps you out!! Have a good day:))

7 0

2 years ago