What is the domain or range of y = one-fourth x minus 6

Mathematics

1 answer:

Sveta_85 [38]3 years ago

4 0

Answer:

domain and range will be ( negative infinity, positive infinity

You might be interested in

Please help which should I choose

Aleksandr [31]

<h3>Answer: Choice A. Graph (1)</h3>

Reasoning:

If it is at all possible to draw a single vertical line through more than one point on the curve, then the graph is not a function. With graphs (2), (3) and (4), we can draw a vertical line through more than one point on those curves, so they aren't functions. Graph (1) is the only thing left. This graph is a function because it is not possible to draw a single vertical line through more than one point. It passes the vertical line test. Any input (x) leads to exactly one and only one y output.

Nice work on getting the correct answer when you chose "graph (1)".

7 0

2 years ago

1 point) Use Stoke's Theorem to evaluate ∫CF⋅dr∫CF⋅dr where F(x,y,z)=xi+yj+1(x2+y2)kF(x,y,z)=xi+yj+1(x2+y2)k and CC is the bound

Drupady [299]

Answer:

Step-by-step explanation:

Thinking process:

$\int\limits^a_b {cF} \, .dr$

= $\int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx curlFdS$ by Stoke's Theorem

= $\int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< z_x,-z_y, 1 > dA\\= \int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< 2x, 2y, 1 > dA$ since z = $25-x^{2} -y^{2} \\= 0$