A 50kg hiker is standing on the edge of a cliff. Find the hiker’s gravitational potential energy if the cliff is 30m high. (Show
2 answers:
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Answer:
Explanation:
As per Kepler's III law we know that time period of revolution of satellite or planet is given by the formula
now for the time period of moon around the earth we can say
here we know that
= mass of earth
Now if the same formula is used for revolution of Earth around the sun
here we know that
= mass of Sun
now we have
Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
B is magnetic field
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.