A dipeptide is formed by the process of dehydration synthesis, which in this case allows two amino acids to come together and form a larger molecule plus water.
Add 4H2 in the reactant side, that will give you 4H2O in the product side.
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Answer:</h3>
2.47 × 10^24 molecules
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Explanation:</h3>
One mole of a compound contains molecules equivalent to the Avogadro's number, 6.022 × 10^23.
That is, 1 mole of a compound = 6.022 × 10^23 molecules
Therefore,
1 mole of Na₂CO₃ = 6.022 × 10^23 molecules
Thus, we can calculate the number of molecules in 4.1 moles of Na₂CO₃
we get,
= 4.1 moles × 6.022 × 10^23 molecules
= 2.47 × 10^24 molecules
Hence, 4.1 moles of Na₂CO₃ contains 2.47 × 10^24 molecules
# An alkaline compound
# High melting and boiling point
Answer: Raw data, perhaps.
Explanation: I'm not certain what the question is seeking for an answer, but I would suggest "raw data" would be a reasonable choice. It reflects the data was recorded, but not yet processed to provide a conclusion or observation.
If one were a bit snarky, other possiblities include
- a pile of dung
- my labmate's scrawls, or
- the best web results I could find
