Answer:
Q = 3139.5 j
Explanation:
Given data:
Mass = 50 g
Initial temperature = 25°C
Final temperature = 95°C
Specific heat capacity = 0.897 j/g.°C
Heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 95°C - 25°C
ΔT = 70°C
Q = m.c. ΔT
Q = 50 g× 0.897 J/g.°C ×70°C
Q = 3139.5 j
Answer:
6 moles of CuCl₂ will produced 4 moles of AlCl₃ .
Explanation:
Given data:
Moles of CuCl₂ = 6 mole
Moles of AlCl₃ produced = ?
Solution:
3CuCl₂ + 2Al → 2AlCl₃ + 3Cu
Now we will compare the moles of CuCl₂ with AlCl₃ .
CuCl₂ : AlCl₃
3 : 2
6 : 2/3 ×6 = 4 mol
So, 6 moles of CuCl₂ will produced 4 moles of AlCl₃ .
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