True or False ?

Help me !! 10/7 x 9/8 7/9 x 8/10

FromTheMoon [43]

Answer:

Step-by-step explanation:

10/7 x 9/8 = 90/56 = 45/28.

7/9 x 8/10 = 56/90 = 28/45

If you want to multiply these, the answer is (28*45) / 28/45) = 1.

5 0

1 year ago

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Cooling towers are used to remove or expel heat from a process. A cooling tower's walls are modeled by x squared over 324 minus

olchik [2.2K]

The width of the cooling tower at the base of the structure will be A. 36 meters.

<h3>How to calculate the width?</h3>

From the information given, the towers walls are modeled by x²/324 - (y² - 90)²/1600.

Therefore, the width of the cooling tower at the base of the structure will be:

= 2 × ✓324

= 2 × 18

= 36

In conclusion, the width is 36 meters.

Learn more about width on:

brainly.com/question/25855344

#SPJ1

3 0

1 year ago

What is the approximate volume of a cone with a radius of 15 cm and a height of 4 cm? Round your answer to the nearest hundredth

vichka [17]

Answer:

Volume of a cone $=942.86cm^3$

Step-by-step explanation:

Given that the radius of a cone is 15cm and its height is 4cm

That is r=15cm and h=4cm

To find the volume of a cone :

volume of a cone $=\frac{\pi r^2h}{3}$ cubic units

Now substitute the values in the formula we get

volume of a cone $=\frac{(\frac{22}{7}) (15)^2(4)}{3}$

$=\frac{(\frac{22}{7}) (225)(4)}{3}$

$=\frac{19800}{21}$

$=942.857$

Now round to nearest hundredth

$=942.86$

Therefore Volume of a cone $=942.86cm^3$

6 0

2 years ago

What does the E in an electrode code stands for?

dalvyx [7]

Answer:

The “E” indicates an arc welding electrode. The first two digits of a 4-digit number and the first three digits of a 5-digit number stand for tensile strength. So, “1” stands for an all position electrode, “2” for a flat and horizontal electrode, and “4” for a flat, horizontal, vertical down and overhead electrode

3 0

2 years ago

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The table shows how many books the students in Bergdalsskolan list during the summer. There were 48 students who list 4 books. a

Juliette [100K]

Step 1:

First, find the total number of students.

Let the total number of students = m

Step 2:

Find the total number of students using the percentage of 4 books.

48 students listed 4 books with a percentage of 16%

$\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{ }\times\text{ m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48 }\times\text{ 100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}$

Hence, there are 300 students.

a)

$\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{ }\times\text{ 300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72 students} \end{gathered}$

72 students had 1 book.

b) What percentage more read 2 books than 4 books?

percentage that read 2 books = 36%

percentage that read 4 books = 16%

36 - 16 = 20%

There are 20% students that read 2 books than 4 books.

8 0

10 months ago