Answer:-
27.38%
Explanation:-
Molecular weight of sodium hydrogen carbonate NaHCO3
= 23 x 1 + 1 x 1 + 12 x 1 + 16 x 3
= 84 gram
Total sodium Na present in NaHCO3 = 23 x 1 = 23 gram
Percentage of sodium present=
Total sodium x 100/ (Total molecular weight)
= 23 x 100 / 84
= 27.38 %
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Answer:
See Explanation
Explanation:
Let us find the number of moles of each element
For iron = 2.24g/56 = 0.04 moles
For oxygen = 0.96 g/16 = 0.06 moles
Then we divide by the lowest ratio;
0.04/0.04 and 0.06/0.04
1 and 2
We Thus obtain 1 : 1.5
Multiplying through by 2 we have; 2 : 3
The formula of the oxide formed is Fe2O3
The balanced equation is;
4Fe + 3O2 ------> 2Fe2O3