B
mass of solute - 4.0 g
mass of solution - 100g + 4.0g = 104g
4/104 = 0.03846
0.03846 • 100 = 3.8%
Answer:
A
Explanation:
No temperature change was observed, hence the change is neither exothermic nor endothermic. Hence the answer is A.
For a normal boiling point of a liquid is 282 °C, the temperature is mathematically given as
T2=181.55°C\
<h3> What
temperature (in °C) would the
vapor pressure be 0.500 atm? </h3>
Generally, the equation for the gas is mathematically given as
ln(p1/p2)=dHvap/R(1/T2-1/T1)
Therefore
ln(1/0.26)=23500/8.214(1/T2-1/555)
T2=181.55^C
In conclusion
T2=181.55°C
Read more about Temperature
brainly.com/question/13439286
Something like that wouldn't dissolve in oil
Answer: False
Explanation:
Depending on the situation it can be shorter or longer than 10 days