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2 years ago

HELP WHAT IS THE ANSWER TO ANY OF THESE !!!

Chemistry

2 answers:

photoshop1234 [79]2 years ago

8 0

Number 4 is
-Oxidation occurs at the anode, while reduction occurs at the cathode. Recharging a battery involves the conversion of electrical energy to chemical energy. During recharging, there is movement of electrons from an external power source to the anode, and on the other side electrons are removed from the cathode.

maks197457 [2]2 years ago

7 0

Answer:

3. They stop producing because they eventually run out of the anode metal so the reaction can not go on.

4. They reverse the flow of electrons when the voltage is above what it needs to go normally.

Explanation:

3. as the reaction occurs the cathode is gaining electrodes as the anode loses them so it gets to a point where the anode and shrunk down so much that it can't give off anymore electrons and that is when the battery stops.

4. lets say you have a cell with a voltage of 1.05 then you would need a voltage higher than that to make it go in reverse and recharge itself.

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Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p

Butoxors [25]

Answer:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

$BiO_3^-\rightarrow Bi^{3+}$

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

$(Bi^{5+}O_3)^-\rightarrow Bi^{3+}$

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

$6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O$

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

$6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Then, we accommodate the waters to obtain:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Best regards!

7 0

2 years ago

Which statement best describes the compressibility of a gas?

atroni [7]

Hey there!

The answer to this question would most likely be the 3rd choice, (option C)

Increasing the pressure on a gas decreases the volume

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

7 0

2 years ago

What is the pressure of 0.5 mol of nitrogen gas in a 5 L container at 203 K

vlada-n [284]

Answer:

=1.666 liters

Explanation:

1 mole of a has at standard temperature and pressure occupies a volume of 22.4 liters.

0.5 moles of nitrogen occupy a volume of (0.5 moles×22.4 dm³/mol)/ 1

=11.2 liters.

Standard pressure= 1 atmosphere (Atm)

Standard temperature = 273.15 Kelvin

According to Combined gas equation, P₁V₁/T₁=P₂V₂/T₂

Let us take the conditions under standard conditions as the reference, with the subscript 1 and the conditions under the 5L container to be scenario 2 with subscript 2.

Therefore P₂ =P₁V₁T₂/T₁V₂

Substituting for the values we get:

P₂= (1 atm× 11.2L ×203K)/ (273K×5L)

=1.666 atm

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2 years ago

What are the Number of molecules of 14 grams of NO2

algol [13]

6.022 x 1023 atoms are in 14 grams of NO2

5 0

2 years ago

What is the difference between corrosion and rusting

BartSMP [9]

Answer:

Corrosion is the process of deterioration of materials as a result of chemical, electrochemical or other reactions. Rusting is a part of corrosion and is a chemical process which results in the formation of red or orange coating on the surface of metals. ... Rust or rusting can affect only iron and its alloys.

Explanation:

4 0

2 years ago