Answer:
Step-by-step explanation:
We can model the string as a hypergeometric distribution, as each bit has two possible values, 1 or 0, and the chance of a 1 or 0 changes with every bit, as there are a finite number M of 0's and N of 1's and every bit takes one of those values.
If M+N (total size of the string) >> r (number of trials), we could model it as a binomial distribution as the probability of a 1 or 0 wouldn't change in a significant amount with every bit, but as we don't know the magnitude of M+N and r, we follow up with hypergeometric distribution.
The distribution has the following formula for probability:
Where k is the number of sucesses, K is how many total sucess states are in the population, N is the population size and n is the number of draws.
For our case, a 1 would be a sucess, i.e. k the number of 1's we want to know the probability, N our total number of 1's, M+N the length of the string (population size) and we want to analyse what happens in the first r bits (number of draws):
To find this out multiply 2 * 2 * 2 * 2 to get 16 possible combinations
I think the answer is 16=x
The answer is C because it equals 9
The answer is 6. 49 you welcome :)