Answer: Volume occupied by given neon sample at standard condition is 123.84 L.
Explanation:
Given: 
= 105 L, 
, 
= 985 torr
At standard conditions,
= 273 K, 
= 760 K, 
= ?
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that volume occupied by given neon sample at standard condition is 123.84 L.
Explanation:
total heat = Heat required to convert 2 kg of ice to 2 kg of water at 0 °C + Heat required to convert 2 kg of water at 0 °C to 2 kg of water at 20 °C.
Heat=mhfg+mCpΔT
Here, m ( mass of ice) = 2 kg
hfg (latent heat of fusion of ice) = 334 KJ
Cp of water (specific heat) = 4.187 KJ/Kg-K
ΔT(Temperature difference) = 20 °C
Therefore, Heat required = 2 x 334 + 2 x 4.187 x (20 - 0 )
Heat reqd= 835.48 KJ
Therefore, to melt 2 kg of ice 835.48 KJ of heat is required.
Answer:
All substances can be characterized by their unique sets of physical and chemical properties. Properties that can be determined without changing the composition of a substance are referred to as physical properties. Characteristics such as melting point, boiling point, density, solubility, color, odor, etc.
