Answer:
V=5.333cubit unit
Step-by-step explanation:
this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1
The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z
The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below
V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.
CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:
<span>y = -5 cos x is a basic (simple) variation of the basic trig function y = cos x.
The given </span>y = -5 cos x could be re-written as <span>y = -5 cos 1x.
Compare this to the most general form: y = a cos bx.
Here we see that the coefficient b equals 1.
There is a rule for finding the period of such a function: Period = 2pi/b.
Since b = 1 here, the Period here is 2pi/1, or simply 2pi.
Please stop saying "I'm terrible with math." That does not help you at all. Say, instead, "With just a little help I could understand this just fine."</span>
Answer:
Step-by-step explanation:
(4/5)n = (2/3)
move 4/5 to the right
n = (2/3)/(4/5)
n = 5/6
Attached solution and work.
