Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
If this is represented by a linear function, then we know that the amount of money decreases at an unchanging amount. Knowing this, and knowing that on day 8, she had 2400, we simply just add 2400 to 8 100's:
2400 + 8*100 = 2400 + 800
Carrie initially had $3200, or Option C.
I could not get it to work with all of those numbers. The only number that caused an issue was 29. I used 28 instead and it worked. I'm not sure if 29 was a typo, but I couldn't get 29 to work.
The quotient of x + 1 StartLongDivisionSymbol x squared + 3 x + 2 EndLongDivisionSymbol is x+2
Step-by-step explanation:
We need to find quotient of x^2+3x+2 divided by x+1
The division is shown in figure attached.
Quotient: x+2
Remainder: 0
The quotient of x + 1 StartLongDivisionSymbol x squared + 3 x + 2 EndLongDivisionSymbol is x+2
The intercepts are -2 and -7 on the x-axis