<span>b • (6a2 - 3ab - 4a + 6q - 3)</span>
A- the length of the side of a square
P = 16
P = 4a → 4a = 16 |:4 → a = 4
The diagonal of the square: d = a√2
therefore d = 4√2
Answer:
-3 < x ≤ -1
Step-by-step explanation:
we know that
The solution of the graph is equal to the interval
All real numbers greater than -3 and less than or equal to -1
so the combined inequality is equal to -3 < x ≤ -1!!!!
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Answer:
C. 3√2 units
Step-by-step explanation:
The diagonal of a square is √2 times the side length. For a square with side length 3, the diagonal is 3√2.
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If you like, you can see this using the Pythagorean theorem.
d² = s² + s² . . . . . where d is the diagonal, and s is the side
d² = 2s²
d = √(2s²) = s√2
For s=3, ...
d = 3√2
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