Finding Distance in the Coordinate Plane
1 answer:
The distance between the two points (-1, 4) and (5, 4) is 6 units.
<u>Step-by-step explanation:</u>
The given Coordinate points are (-1, 4) and (5, 4).
The points are considered as (x1,y1) and (x2,y2).
Here,
x1 = -1 and x2 = 5
y1 = 4 and y2 = 4
<u>The distance formula is given by :</u>
Distance =
<u>To find the distance between these two points :</u>
The distance formula is used,
Distance =
⇒ √(6)²
⇒ √36
⇒ 6
Therefore, the between the points is 6 units.
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First you have to find the intercepts!
To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~
To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~