the answer is A but im just guessing ya know?
6/10 is the answer but if you want it simplified the the answer would be 3/5.
You need three non-collinear points to name a plane.
Non-collinear means "not on the same straight line". So these three points can't all lie on the same straight line. If three points do lie on the same straight line, then it is impossible to generate a single unique plane.
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Answer:
m = - 1/4
Step-by-step explanation:
When two line is perpendicular to each other the product of them is - 1
So let the other line be B
Gradient of B = t
Gradient of A = 4
therefore m = - 1/4