In arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b. SOOO, no there can be a lower number then both multiplied by each other.
Answer:
Step-by-step explanation:
because both equations do not have matching numbers for the x or y variable, and both equations are positive you are going to have to multiply each equation by a number so that there will be at least one variable with the same number but with opposite signs.
it does not matter which variable you choose.
lets use y because 2 and 3 are smaller then 2 and 5.
so lets multiply the first equation by 2 in order to get y equal to 6.
2(2x)+2(3y)=(2)6
(do not forget to multiply what the equation is equal to also)
4x+6y=12
now for the second equation we need y to equal negative 6
-3(5x)+-3(2y)=-3(4)
-15x-6y=-12
now lets put the 2 new equations next to each other and see what we can cancel out
4x+6y=12
-15x-6y=-12
-11x=0
x=0
now plug 0 in for x and solve for y (it does not matter which of the 4 equations you choose to solve.
2(0)+3y=6
3y=6
y=2
so your answer is x=0, y=2
Answer:
Cost of one pencil: 
Cost of one eraser: 
Step-by-step explanation:
Let be "p" the cost in dollars of one pencil and "e" the cost in dollars of one eraser.
Based on the information given in the exercise, you can set up the following system of equations:
You can use the Elimination Method to solve the system of equations.
Multiply the first equation by -3 ad the second one by 4. Then add the equations and solve for "e":
{
Substitute the value of "e" into any original equation and solve for "p":
Answer:
5/8 is smaller.
Step-by-step explanation:
A ratio is just a different type of fraction, a 5:8 ratio means 5/8 which is 0.625. A 7:9 ratio equals 7/9 which is 0.777777
Then to compare them you see which is smaller or bigger.
0.77777 is bigger than 0.625 so we know that 0.77777777 which was the 7:9 ratio is the bigger one.
