So how would you break down the problem(2x-5)^2=49
2 answers:
First, simplify the equation. 4x2−20x+25=<span>49 </span> Step 2: Subtract 49 from both sides. <span><span>4x2−20x+25</span>=<span>49 - 49 </span></span><span><span>4x2−20x</span>−24 </span>=<span>0 </span> Step 3: Factor left side of equation. <span><span><span>4<span>(x+1)</span></span><span>(x−6)</span></span>=<span>0 </span></span>Step 4: Set factors equal to 0. <span><span><span>x+1</span>=<span><span><span>0<span> or </span></span>x</span>−6</span></span>=0Your answers: </span><span><span>x= <span>− <span><span>1 <span> or </span></span>x </span></span></span>=6 </span><span> </span><span> </span>
To solve this you first expand the brackets. 4x^2 - 20x + 25 = 49 Then make it equal 0. 4x^2 - 20x - 24 = 0 Now solve the quardratic. x^2 - 5x - 6 = 0 (x - 6)(x + 1) = 0 x = 6 or x = -1
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Si me amp Jake I help u it’s Definitely
D because your making the shape smaller 2 times
The pythagorean theorem states that a^2+ b^2=c^2. Final answer: None of the above
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Step-by-step explanation:
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Step-by-step explanation: