Answer:
Option A is right
Step-by-step explanation:
Given that approximately 52% of all recent births were boys. In a simple random sample of 100 recent births, 49 were boys and 51 were girls. The most likely explanation for the difference between the observed results and the expected results in this case is
A) variability due to sampling
-- True because there is a slight difference whichmay be due to sampling fluctuations.
B) bias
False because given that 100 random births selected
C) nonsampling error
False. There is no chance for systematic error here.
d) Confounding: There is no confounding variable present inchild birth since each is independent of the other
e) a sampling frame that is incomplete
False because the sampling is done correctly.
Answer:
3/15 is pauls probability simplified to 1/5
7/ 14 is Kim's probability simplified to 1/2
so, the overall probability would be 1/10
Answer: 0.0010
Step-by-step explanation:
Given the following :
Population Mean(m) = 4.2 years
Sample mean (s) = 3.9
Standard deviation (sd) = 0.6
Number of samples (n) = 38
Calculate the test statistic (z) :
(sample mean - population mean) / (sd / √n)
Z = (3.9 - 4.2) / (0.6 / √38)
Z = (- 0.3) / (0.6 / 6.1644140)
Z = -0.3 / 0.0973328
Z = - 3.0822086
Z = - 3.08
From the z table :
P(Z ≤ - 3.08) = 0.0010
Answer:
Step-by-step explanation:
Let d represent the number of dimes. Then 81-d is the number of nickels and the total value in cents is ...
10d +5(81-d) = 530
5d +405 = 530 . . . eliminate parentheses
d +81 = 106 . . . . . divide by 5
d = 25 . . . . . . . . . subtract 81; number of dimes
81 -d = 81 -25 = 56 . . . . . number of nickels
There are 25 dimes and 56 nickels in the box.
_____
<em>Comment on the method of solution</em>
It usually works well to let the variable represent the amount of the highest-value contributor (dimes). This keeps the numbers positive as the solution progresses.
Which of the following is the best way
King Middle School?
of selecting a random sample from students at select every student from one grade.
use the student directory, pick one student's name by chance, and then pick another student's name.
