Question

You start with 6 moles of an acid, 2 moles dissociate into the conjugate base, what is the percent ionization

Answer 1

Answer:

33 %

Explanation:

Step 1: Given data

Initial moles of the acid (nHA(0)): 6 mol

Moles of the conjugate base at equilibrium (nA⁻(eq))

Step 2: Write the balanced generic acid dissociation reaction

HA(aq) ⇄ A⁻(aq) + H⁺(aq)

Step 3: Calculate the percent ionization

We will use the following expression.

$\alpha = \frac{nA^{-}(eq)}{nHA(0)} \times 100 \% = \frac{2mol}{6mol} \times 100 \% = 33 \%$