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2 years ago

F(x)=2(x+1)^2-2 What is the vertex

Mathematics

1 answer:

Bumek [7]2 years ago

8 0

Answer:

(-1,-2)

Step-by-step explanation:

Let's bring back to memory vertex formula for parabolas.

$y=a(x-h)^{2}+k$

Where (h,k) is the vertex.

In $f(x)=2(x+1)^{2}-2$

The vertex is (-1,-2)

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Solve for x.

Nonamiya [84]

$-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\text{use distributive property}\\\\-\dfrac{2}{\not3_1}\cdot\not3^1x+\dfrac{8}{3}+3x=\dfrac{5}{6}\\\\-2x+3x+\dfrac{8}{3}=\dfrac{5}{6}\ \ \ \ |-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8\cdot2}{3\cdot2}\\\\x=\dfrac{5}{6}-\dfrac{16}{6}\\\\\boxed{x=-\dfrac{11}{6}}$

Other method:

$-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\cdot6\\\\2(-2)(3x-4)+18x=5\\\\-4(3x-4)+18x=5\ \ \ \ |\text{use distributive property}\\\\-12x+16+18x=5\ \ \ \ |-16\\\\6x=-11\ \ \ \ |:6\\\\\boxed{x=-\dfrac{11}{6}}$

7 0

2 years ago

Read 2 more answers

HELP SOLVE THANK YOU!

Lera25 [3.4K]

Answer:

Solution 1: 1+1 $\sqrt{3}$

Solution 2: 1- $1\sqrt{3}$

Step-by-step explanation:

x^2-2=2x

x^2-2x-2=0

Use quadratic equation.

(-b+- $\sqrt{b^2-4ac}$ )/2a

(2+- $\sqrt{(-2)^2-4*1*-2}$ )/2

(2+- $\sqrt{(4+8})$ )/2

(2+- $\sqrt{12}$ )/2

Solution 1: (2+2 $\sqrt{3}$ )/2=1+1 $\sqrt{3}$

Solution 2: 1- $1\sqrt{3}$

4 0

1 year ago

Read 2 more answers

Which expression is equivalent to 7/10-2/10

ki77a [65]

Solution:

we have been asked to find

The expression is equivalent to $7/10-2/10$

we can simplify the given expression as below

$\frac{7}{10}-\frac{2}{10}=\frac{7-2}{10}\\ \\ \Rightarrow \frac{7}{10}-\frac{2}{10}=\frac{5}{10}\\ \\ \text{Simplify we get}\\ \\ \frac{7}{10}-\frac{2}{10}=\frac{1}{2}\\$