Try 90
triangles can be 30:60:90
Answer:
Step-by-step explanation:
Once again, we have a problem with the |x| in it, so like last time, every number that is the outcome within those brackets, is positive.
Let us check:
A. x = 21 over 4 and x = -11 over 4
This one is a very simple to say no to, as we are talking about decimals (if you convert into decimals at this point), as in -16 there are no decimals.
False.
B. x = -1 and x = 9
-1 is correct. But 9 is not. Why? Here:
9 + 5 is 14
14 the multiplied by -4 does not equal -16
False.
C. x = -1 and x = -9
Like what I said before, -1 is correct, now in this answer, -9 is also correct.
Unlike the last one, this one is -9 + 5 which is -4, then since it is inside the positive brackets, the number 4 becomes positive.
4 * -4 = -16
True.
The last one is incorrect. You know why
;)
Answer:
5/12
Step-by-step explanation:
Total ear buds in Mrs. Jackson’s class = 5/8
Number of black ear buds in Mrs. Jackson’s class = 2/3
What fraction of
the scholars have black ear buds?
2/3 of the scholars have black ear buds in Mrs. Jackson’s class
2/3 of 5/8
= 2/3 × 5/8
= 10/24
= 5/12
Fraction of the scholars that have black ear buds = 5/12
<span>1.2555⋅<span>10^<span>−<span>6
</span></span></span></span>Explanation:
<span><span><span>(1.08⋅<span>20<span>−3</span></span>)</span><span>(9.3⋅<span>10<span>−3</span></span>)</span>=<span>1.08<span><span>(20)</span>3</span></span>⋅<span>9.3<span><span>(10)</span>3</span></span>=<span><span>1.08⋅9.3</span><span>8⋅<span>106</span></span></span>=1.2555</span><span>⋅<span>10<span>−6</span></span></span></span>
Answer:
Step-by-step explanation:
Having the information on how many events there are and how many people in each event there would help me personally solve this
what i can tell you is its a probability thing a tree diagram is starting with something, like flipping a coin, and creating a branch for heads and tails, 0.5 for each branch. like the attachment I have on here. there's only 2 probable results from a coin, but if I have 5 events with 50 competitors I've created a lot more probable outcomes, it also depends on the events, if one of my competitors in 6'9" and ones 5'2" and the event is a dunk contest it would be slightly unfair and the probability of the person who is 5'2" changing your tree diagram :)