<u>Answer:
</u>
Distance traveled = 70 meters
Displacement = 36.06 meters
<u>Explanation:
</u>
Let north be positive Y and east be positive X
10 meters north, displacement = 10 j meters
20 meters west, displacement = -20 i meters
40 meters south, displacement = -40 j meters
Total displacement = (10 j - 20 i – 40 j) meters = (- 20 i - 30 j) meters
Magnitude of displacement =
Distance traveled = 10+20+40 = 70 meters
so, 444 eggs would have been released in 37yrs
A 100kg crate slides along a floor with a starting velocity of 21 m/s. If the force due to friction is 8N, then, it will take 262.5 s for the box to come to rest.
We'll begin by calculating the declaration of the box. This can be obtained as follow:
Force (F) = –8 N (opposition)
Mass (m) = 100 Kg
<h3>Deceleration (a) =? </h3>
<h3>F = ma</h3>
–8 = 100 × a
Divide both side by 1000
<h3>a = –0.08 ms¯²</h3>
Therefore, the deceleration of the box is –0.08 ms¯²
Finally, we shall determine the time taken for the box to come to rest. This can be obtained as follow:
Deceleration (a) = –0.08 ms¯²
Initial velocity (u) = 21 ms¯¹
Final velocity (v) = 0 ms¯¹
<h3>Time (t) =.? </h3>
<h3>v = u + at</h3>
0 = 21 + (–0.08×t)
0 = 21 – 0.08t
Collect like terms
0 – 21 = –0.08t
–21 = –0.08t
Divide both side by –0.08
<h3>t = 262.5 s</h3>
Therefore, it will take 262.5 s for the box to come to rest.
Learn more: brainly.com/question/14446351