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2 years ago

What is the formula for the area of a triangle?

Mathematics

2 answers:

Nana76 [90]2 years ago

7 0

Answer:

$\Large \boxed{\mathrm{\bold{C} }}$

Step-by-step explanation:

We can find the area of the triangle when two sides are given and the angle in between the two sides.

$\displaystyle A=\mathrm{\frac{1}{2} bc \cdot sinA}$

b and c are the sides and A is the angle in between b and c.

Semmy [17]2 years ago

5 0

Answer: c. (1/2) bc sin A

<u>Step-by-step explanation:</u>

You can find the area of a triangle using trigonometry if you know the lengths of two sides and the measure of the included angle using the following formula:

$A=\dfrac{1}{2}ab\sin C$

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Is x and x2 like terms or unlike terms

babymother [125]

Like terms" are terms whose variables (and their exponents such as the 2 in x2) are the same. In other words, terms that are "like" each other. Note: the coefficients (the numbers you multiply by, such as "5" in 5x) can be different.

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2 years ago

This graph shows a proportional relationship.

Kamila [148]

Answer:

The constant of proportionality is 0.3, or K=0.3.

Step-by-step explanation:
The chart I attached shows points that are plotted on the proportional line. In order to find the constant of proportionality from these points, you have to divide the amount of change by the number of years. For example, 3 divided by 10 or 6 divided by 20. This results in 0.3, which means that every year, there is 0.3 centimeters of change in the sea level.

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2 years ago

Write 27/40 as a decimal.

Alecsey [184]

Answer:

0.675

Step-by-step explanation:

27/40

- Divide each number by 10

2.7/4

- Multiply each number by 25

67.5/100

Convert that into a decimal. :)

4 0

2 years ago

Read 2 more answers

What multiplication fact could you use to find a number that can be divided into 8 and by 9?

s344n2d4d5 [400]

72 is a number that can divide into 8 and by 9 also

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2 years ago

What is the form of the two squares identity?

zvonat [6]

Answer:

Step-by-step explanation:

Consider all options:

A. False, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ab-cd)^2+(ac+bd)^2=a^2b^2-2abcd+c^2d^2+a^2c^2+2abcd+b^2d^2=\\ =a^2b^2+c^2d^2+a^2c^2+b^2d^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2\neq a^2b^2+c^2d^2+a^2c^2+b^2d^2$

B. False, because

$(a^2-b^2)(c^2+d^2)=a^2c^2+a^2d^2-b^2c^2-b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2-b^2c^2-b^2d^2\neq a^2c^2+b^2d^2+a^2d^2+b^2c^2$

C. False, because

$(a^2+b^2)(c^2-d^2)=a^2c^2-a^2d^2+b^2c^2-b^2d^2\\ \\(ac+bd)^2-(ad+bc)^2=a^2c^2+2abcd+b^2d^2-a^2d^2-2abcd-b^2c^2=\\=a^2c^2+b^2d^2-a^2d^2-b^2c^2\\ \\a^2c^2-a^2d^2+b^2c^2-b^2d^2\neq a^2c^2+b^2d^2-a^2d^2-b^2c^2$

D. True, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2= a^2c^2+b^2d^2+a^2d^2+b^2c^2$

6 0

2 years ago