Answer:
0.19
Step-by-step explanation:
12u->2.28
1u-> 2.28 /12
=0.19
Simplified, it"s y=-3/2x+22.5
Take the 4cm side and the 6cm side.
If you hook them together at one end, then there's no way they can reach the ends of the 11cm side. The farthest they can reach is 10cm.
That's what choice-B says.
There are 5 solutions for this system.
x^2 + 4y^2 = 100 ____1
4y - x^2 = -20 ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80 (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y : y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2 x = /100 - 4y^2 (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
Answer: 18 1/6 feet
Step-by-step explanation:
From the question, we are informed that the rectangular sand box has a length of 5 1/3 feet and a width of 3 3/4 feet.
The perimeter would be calculated as:
= 2(length + width)
= 2( 5 1/3 + 3 3/4)
= 2( 5 4/12 + 3 9/12)
= 2( 8 13/12)
= 2 (9 1/12)
= 2 × 9 1/12
= 2 × 109/12
= 218/12
= 18 2/12
= 18 1/6 feet