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konstantin123 [22]

2 years ago

7

Translate the following words into equations.

2 answers:

Rina8888 [55]2 years ago

3 0

Answer:

I. 15=9+n

II. 28/n=7

Step-by-step explanation:

More than a number, n= number

Quotient(divide)

tatuchka [14]2 years ago

3 0

I. 15=x+9

II. 28/x = 7

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The complement of an angle is three times the measurement of the angle. Find the measurement of the larger angle.

olganol [36]

We know that two complements add up to 90.
Let's call the smaller angle x and the larger y.
3x = y
x + y = 90
We can use simple substitution.
x + 3x = 90
4x = 90
x = 22.5

Then, since we know that 3x=y, we can find the larger angle.
3*22.5 = 67.5

4 0

3 years ago

Please help: (picture)

Slav-nsk [51]

We need to solve the speed formula for d. To do so, let's start by moving the number of the left hand side:

$\frac{S}{356} = \sqrt{d}$

Square both sides to get rid of the square root:

$\frac{S^2}{126736} = d$

Now plug the known value of the speed to find the distance:

$d = \frac{140^2}{126736} = \frac{19600}{126736} \approx 0.15465$

So the closest answer is the last one: d=0.155km

3 0

2 years ago

Find the x and y intercept of 2x + 5y - 20

UNO [17]

Answer:

x=(10,0)

y=(0,4)

Step-by-step explanation:

Rewrite the equation so it is 5y=2x-20

Multiply both sides by 5

Then figure out the equation and you get the x intercept

Then put 10 into your new equation in the x spot and thats how you get y

Hope this helps:)

If my explaining is not good you can also use Math_way and it shows you all th steps too.

6 0

2 years ago

Solve the equation to get the value y

tia_tia [17]

Answer:

y=11

x=-4

Step-by-step explanation:

y =-x+7

2x-5y=-7

insert the first equation into the second like so...

2x+5x-35=-7

Now rearrange...

2x+5x=-7+35

Now solve...

7x=-28

x=-4

Now incert x in any equation...

y=4+7

y=11

5 0

2 years ago

Read 2 more answers

Will mark brainliest!!!plz helppp

muminat

Answer:

(5,-6)

Step-by-step explanation:

ONE WAY:

If $f(x)=x^2-6x+3$ , then $f(x-2)=(x-2)^2-6(x-2)+3$ .

Let's simplify that.

Distribute with $-6(x-2)$ :

$f(x-2)=(x-2)^2-6x+12+3$

Combine the end like terms $12+3$ :

$f(x-2)=(x-2)^2-6x+15$

Use $(x-b)^2=x^2-2bx+b^2$ identity for $(x-2)^2$ :

$f(x-2)=x^2-4x+4-6x+15$

Combine like terms $-4x-6x$ and $4+15$ :

$f(x-2)=x^2-10x+19$

We are given $g(x)=f(x-2)$ .

So we have that $g(x)=x^2-10x+19$ .

The vertex happens at $x=\frac{-b}{2a}$ .

Compare $x^2-10x+19$ to $ax^2+bx+c$ to determine $a,b,\text{ and } c$ .

$a=1$

$b=-10$

$c=19$

Let's plug it in.

$\frac{-b}{2a}$

$\frac{-(-10)}{2(1)}$

$\frac{10}{2}$

$5$

So the $x-$ coordinate is 5.

Let's find the corresponding $y-$ coordinate by evaluating our expression named $g$ at $x=5$ :

$5^2-10(5)+19$

$25-50+19$

$-25+19$

$-6$

So the ordered pair of the vertex is (5,-6).

ANOTHER WAY:

The vertex form of a quadratic is $a(x-h)^2+k$ where the vertex is $(h,k)$ .

Let's put $f$ into this form.

We are given $f(x)=x^2-6x+3$ .

We will need to complete the square.

I like to use the identity $x^2+kx+(\frac{k}{2})^2=(x+\frac{k}{2})^2$ .

So If you add something in, you will have to take it out (and vice versa).

$x^2-6x+3$

$x^2-6x+(\frac{6}{2})^2+3-(\frac{6}{2})^2$

$(x+\frac{-6}{2})^2+3-3^2$

$(x+-3)^2+3-9$

$(x-3)^2+-6$

So we have in vertex form $f$ is:

$f(x)=(x-3)^2+-6$ .

The vertex is (3,-6).

So if we are dealing with the function $g(x)=f(x-2)$ .

This means we are going to move the vertex of $f$ right 2 units to figure out the vertex of $g$ which puts us at (3+2,-6)=(5,-6).

The $y-$ coordinate was not effected here because we were only moving horizontally not up/down.

3 0

2 years ago