Answer:
sqrt(13) =x
Step-by-step explanation:
We have 2 right triangles, one on the right and one on the left
The base is 1/2 of 4 or 2 and the height is 3
We can use the Pythagorean theorem to find the hypotenuse
a^2 + b^2 = c^2
2^2 + 3^2 = x^2
4+9 = x^2
13 = x^2
Take the square root of each side
sqrt(13) =x
The value of sin A is equal to
<h3>RIGHT TRIANGLE</h3>
A triangle is classified as a right triangle when it presents one of your angles equal to 90º. In this triangle from the trigonometric ratios or the Pythagoras Theorem (), it is possible finding angles or sides.
<h3>Trigonometric Ratios</h3>
The main trigonometric ratios for a right triangle are presented below.
The question asks the sin A. First, you should find the hypotenuse from Pythagoras Theorem.
Now you can find sin A.
Learn more about trigonometric ratios here:
brainly.com/question/11967894
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The answer is -8
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Explanation:
There are two ways to get this answer
Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8
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The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4
g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8
Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8
Regardless of which method you use, the answer is -8
You can soustracte the first or the second one
and y cancel
x = 6
now you put 6 in x
you can take the first or the second one
6 - y = -2
6 - y = -2
y = -8