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3 years ago

Find f(-3), f(-1), and f(1)

Mathematics

1 answer:

suter [353]3 years ago

3 0

Answer:

I will just show you how to substitute.

Step-by-step explanation:

all you have to do is just plug f(x) into the number you want. So if you see any x's, all you gotta do is plug that number after f for x.

So an example of an equation for one of your number is:

$f\left(x\right)=x^2+x$

you then want to plug the number after f for the x's. (I'm doing f(-3).

$f\left(-3\right)=\left(-3\right)^2-3$

You then should get the equation above.

after that you solve.

$f\left(-3\right)=9-3$

$f\left(-3\right)=6$

just follow these steps and you should be fine :))

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Answer:

$x=\dfrac{3+ \sqrt{29}}{2}, \quad \dfrac{3- \sqrt{29}}{2}$

Step-by-step explanation:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Given quadratic equation:

$x^2-3x-5=0$

Define the variables:

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Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(1)(-5)}}{2(1)}$

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Therefore, the exact solutions to the given quadratic equation are:

$x=\dfrac{3+ \sqrt{29}}{2}, \quad \dfrac{3- \sqrt{29}}{2}$

Learn more about the quadratic formula here:

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