Answer:
=1.666 liters
Explanation:
1 mole of a has at standard temperature and pressure occupies a volume of 22.4 liters.
0.5 moles of nitrogen occupy a volume of (0.5 moles×22.4 dm³/mol)/ 1
=11.2 liters.
Standard pressure= 1 atmosphere (Atm)
Standard temperature = 273.15 Kelvin
According to Combined gas equation, P₁V₁/T₁=P₂V₂/T₂
Let us take the conditions under standard conditions as the reference, with the subscript 1 and the conditions under the 5L container to be scenario 2 with subscript 2.
Therefore P₂ =P₁V₁T₂/T₁V₂
Substituting for the values we get:
P₂= (1 atm× 11.2L ×203K)/ (273K×5L)
=1.666 atm
Answer:
A long uniformly charged wire has charge density λ=0.16μλ=0.16μC/m.
Answer:
Luster of aluminum is Silver-White.
Explanation:
Aluminium is a Silver-White metal which is extracted from the Bauxite ore which can be reddish brown, white, tan, grey-white and tan-yellow in color and have the minerals like Gibbsite, Boehmite and Diaspore which are the minerals of the aluminium.
The Bauxite is the rock from which the Bauxite ore is extracted which have the minerals of the aluminum.
The luster of a metal is the color and shine of it and its shiny appearance.
Aluminium is a light weight metal but have a moderate hardness which makes a wider use of it. Aluminium is used in many places where the weight of the material is kept light but its hardness can be increased by mixing some other metals in it making hard alloy with lighter weight.
It is used in transportation vehicles, buildings, and many other places like Air crafts as the weight should be kept controlled to give a perfect lift to the Air craft.
Equation is as follow,
<span> 2 AgNO</span>₃<span> + MgBr</span>₂<span> </span>→ <span>2 AgBr + Mg(NO</span>₃<span>)</span>₂
According to eq.
339.74 g (2 moles) AgNO₃ produces = 375.54 g (2 moles) of AgBr
So,
22.5 g AgNO₃ will produce = X g of AgBr
Solving for X,
X = (22.5 g × 375.54 g) ÷ 339.74 g
X = 24.87 g of AgBr
Given data:
Mass of copper (m) = 20.0 g
Initial temperature of Copper (T1)= 25 C
Final temperature = T2
Heat absorbed by copper (Q) = 475 J
Specific heat of Copper (c) = 0.385 J/g C
Formula:
Q = mcΔT
= mc(T2-T1)
475 = 20*0.385*(T2-25)
62.08 = T2-25
T2 = 87.08 = 87.1 C