During a school lunch, the cafeteria sold two-fifths as many white milks as chocolate milks. If there were 35 milks sold, how ma
1 answer:
Hello!
As we can see, they sell 2/5 as many white milks and chocolate milks. We can write this as the ratio 2:5. As you can see, we are given the total, which is 35. The total of the ratio in simplest form is 7 (2+5). As you can see, we have to multiply by 5 to get that 7 to 35. Therefore we multiply each part of the ratio by 5 to get our final answer. We can have w represent the white milks while c represents the chocolate milks.
·
=
Therefore there were 25 chocolate milks sold (just to verify 10 is 2/5 of 25).
I hope this helps!
As we can see, they sell 2/5 as many white milks and chocolate milks. We can write this as the ratio 2:5. As you can see, we are given the total, which is 35. The total of the ratio in simplest form is 7 (2+5). As you can see, we have to multiply by 5 to get that 7 to 35. Therefore we multiply each part of the ratio by 5 to get our final answer. We can have w represent the white milks while c represents the chocolate milks.
Therefore there were 25 chocolate milks sold (just to verify 10 is 2/5 of 25).
I hope this helps!
You might be interested in
Answer:
401
Step-by-step explanation:
1. Approach
To solve this problem, one first has to think about the given figure in a certain way. In the figure, one can see that it is a circle attached on either side of a rectangle. To find the perimeter of the figure, one has to find the circumference of the circle and then add two sides of the rectangle to the answer
2. Circumference of the circle
The formula to find the circumference of a circle is;
(pi) or
(pi)
~ diameter times the value (pi)
Normally to find the circumference of a semicircle, one would have to divide this formula by 2, but since in this case, one has to add two congruent semicircles, so therefore, the effect of dividing the equation by two, only to multiply by two again cancels, and hence, there is no need to divide by 2.
Substitute in the values;
(78)(pi)
~ 245
3. Find the perimeter of the entire object
Now, one has to add the two additional sides of the figure, to the circumferences of the semicircles to get the final answer;
78 + 78 + 245
= 401